# SUM OF DICTIONARY VALUES PYTHON

d = "key1": 1,"key2": 14,"key3": 47Is tright here a syntactically minimalistic method to rerevolve the sum of the worths in d—i.e. 62 in this case?

In Python 2 you have the right to protect against making a momentary copy of all the values by using the itervalues() dictionary technique, which retransforms an iterator of the dictionary"s keys:

sum(d.itervalues())In Python 3 you deserve to simply usage d.values() because that strategy was changed to carry out that (and itervalues() was rerelocated considering that it was no longer needed).

You watching: Sum of dictionary values python

To make it much easier to write variation independent code which always iteprices over the worths of the dictionary"s keys, a utility function have the right to be helpful:

import sysdef itervalues(d): rerevolve iter(getattr(d, ("itervalues", "values")>2>)())sum(itervalues(d))This is fundamentally what Benjamin Peterson"s 6 module does.

Sure tright here is. Here is a way to amount the worths of a dictionary.

d = "key1": 1,"key2": 14,"key3": 47sum1 = sum(d for item in d)print(sum1)you deserve to do it making use of the for loop

I feel sum(d.values()) is the most effective method to acquire the sum.

You can additionally attempt the minimize function to calculate the amount along with a lambda expression:

reduce(lambda x,y:x+y,d.values())
phihag"s answer (and also similar ones) won"t occupational in python3.

For python 3:

d = "key1": 1,"key2": 14,"key3": 47sum(list(d.values()))Update! Tright here are complains that it does not work! I simply connect a screenswarm from my terminal. Could be some misenhance in versions etc.

You can consider "for loop" for this:

d = "data": 100, "data2": 200, "data3": 500 complete = 0 for i in d.values(): total += itotal = 800

USE sum() TO SUM THE VALUES IN A DICTIONARY.

Call dict.values() to rerevolve the values of a dictionary dict.Use sum(values) to return the sum of the worths from the previous step.

d = "key1":1,"key2":14,"key3":47values = d.values()#Rerotate worths of a dictionary complete = sum(values)print(total)
simplest/silliest solution:

https://trinket.io/python/a8a1f25353

d = "key1": 1,"key2": 14,"key3": 47s = 0for k in d: s += dprint(s)or if you desire it fancier:

https://trinket.io/python/5fcd379536

import functoolsd = "key1": 1,"key2": 14,"key3": 47s = functools.reduce(lambda acc,k: acc+d, d, 0)print(s)
You can gain a generator of all the worths in the dictionary, then actors it to a list and usage the sum() function to acquire the sum of all the worths.

Example:

c="a":123,"b":4,"d":4,"c":-1001,"x":2002,"y":1001sum(list(c.values()))
Thanks for contributing a response to Stack Overflow!

Please be certain to answer the question. Provide details and share your research!

But avoid

Asking for assist, clarification, or responding to other answers.Making statements based on opinion; back them up via recommendations or personal experience.

To learn even more, see our tips on composing excellent answers.

Article Your Answer Discard

By clicking “Article Your Answer”, you agree to our regards to company, privacy plan and also cookie plan

## Not the answer you're looking for? Browse various other questions tagged python dictionary hash amount or ask your own question.

site design / logo © 2021 Stack Exchange Inc; user contributions licensed under cc by-sa. rev2021.9.2.40142

Your privacy

By clicking “Accept all cookies”, you agree Stack Exreadjust can keep cookies on your gadget and discshed information in accordance through our Cookie Policy.