Skip first line csv python

Possible Duplicate: When handling CSV information, just how carry out I disregard the initially line of data?

I am utilizing python to open up CSV file. I am using formula loop but I have to skip the first row because it has actually header.

You watching: Skip first line csv python

So far I remember was something favor this however it is missing something: I wonder if someone knows the code for what I am trying to execute.

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for row in kidfile: if row.firstline = false: #

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The best means of doing this is skipping the header after passing the file object to the csv module:

with open("myfile.csv", "r", newline="") as in_file: reader = csv.reader(in_file) # skip header next(reader) for row in reader: # take care of parsed rowThis handles multiline CSV headers properly.

Older answer:

Probably you want something like:

firstline = Truefor row in kidfile: if firstline: #skip initially line firstline = False continue # parse the lineAn various other method to achive the very same result is calling readline before the loop:

kidfile.readline() # skip the initially linefor row in kidfile: #parse the line
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edited Apr 24 at 14:34
answered Feb 3 "13 at 16:03

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BakuriuBakuriu
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Tbelow are many kind of means to skip the first line. In addition to those said by Bakuriu, I would add:

via open(filename, "r") as f: next(f) for line in f:and:

with open(filename,"r") as f: lines = f.readlines()<1:>
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answered Feb 3 "13 at 16:06

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AndreaAndrea
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csvreader.next()Rerevolve the following row of the reader’s iterable object as a list, parsed according to the current language.


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answered Feb 3 "13 at 17:04
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user2037553user2037553
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